/* * @brief 题解 * @file c.cpp * @author xiyanxiyan10 * @CreatedTime 2014/10/02 * @LastChanged 2014/10/02 * @note * 规律, 规律题目 * 当 n < 4时无解 * 当 n > 4时，如果n为偶数，则通过前4个数构造24，其余的数两两构造1 * 当 n > 4时 如果n为奇数，则通过前3个数构造24，其余的数两两构造1 */#include#include #include #include #include #include #include #include #include using namespace std;#ifdef DEBUGifstream in;ofstream out;#endif#ifdef DEBUG#define CIN in#define COUT out#else#define CIN cin#define COUT cout#endif#define oddStr "1 * 2 = 2\n2 * 3 = 6\n6 * 4 = 24\n";#define evenStr "3 * 5 = 15\n2 * 4 = 8\n15 + 8 = 23\n23 + 1 = 24\n";#ifdef DEBUGvoid debugInit(void){ string buffer; CIN.open("in", ios::in); COUT.open("out", ios::out); while(getline(CIN, buffer)) COUT << buffer << "\n"; COUT << "Out Put" << "\n"; CIN.close(); CIN.open("in", ios::in);}#endifint main(){#ifdef DEBUG debugInit();#endif int n; CIN >> n; if(n < 4){ COUT << "NO" << "\n"; }else{ COUT << "YES" << "\n"; if(n&0x1){ COUT << evenStr; for(int i = 6; i < n; i+= 2){ COUT << (i + 1) << " - " << i << " = " << "1\n"; COUT << "24 * 1 = 24\n"; } }else{ COUT << oddStr; for(int i = 5; i < n; i+= 2){ COUT << (i + 1) << " - " << i << " = " << "1\n"; COUT << "24 * 1 = 24\n"; } } } return 0;}